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Riešenie

Úloha 14

#include <stdio.h>
#include <conio.h>
#include <stdlib.h>
#include <string.h>

typedef struct uloha {
    char   nazov[30];
    struct uloha *dalsi;
} TUloha;

------------------------------------------------------------------------------
void pridaj(TUloha **z, TUloha **k)
{
  TUloha *p;

  clrscr();

  if (*z == NULL) {
     *z = (TUloha*)malloc(sizeof(TUloha));
     printf("nazov ulohy: ");
     gets((*z)->nazov);
     (*z)->dalsi = NULL;
     *k = *z;
  }
  else {
     p = (TUloha*)malloc(sizeof(TUloha));
     printf("nazov ulohy: ");
     gets(p->nazov);
     p->dalsi = NULL;
     (*k)->dalsi = p;
     (*k) = p;
  }
}
------------------------------------------------------------------------------
void vypis(TUloha *z1, TUloha *z2)
{
  clrscr();
  printf("Zoznam uloh - Front 1\n");
  while (z1 != NULL) {
     printf("\nuloha: %s", z1->nazov);
     z1 = z1->dalsi;
  }

  printf("\n\nZoznam uloh - Front 2\n");
  while (z2 != NULL) {
     printf("\nuloha: %s", z2->nazov);
     z2 = z2->dalsi;
  }
  getch();
}
------------------------------------------------------------------------------
void vybavenie(TUloha *z1, TUloha *z2) /* "tlač" úloh */
{
   TUloha *pom;

   clrscr();
   printf("Prebieha tlac !!!\n");
   while (z1 != NULL) {
      pom = z1;
      z1  = z1->dalsi;
      printf("\nTlacim z F1:  %s", pom->nazov);
      free((void*)pom);
   }

   while (z2 != NULL) {
      pom = z2;
      z2  = z2->dalsi;
      printf("\nTlacim z F2:  %s", pom->nazov);
      free((void*)pom);
   }

   getch();
}
------------------------------------------------------------------------------
int main(void)
{
  TUloha *zac1, *kon1;  /* prvý  front */
  TUloha *zac2, *kon2;  /* druhý front */
  int c;

  zac1 = kon1 = NULL;
  zac2 = kon2 = NULL;

  /* menu */
  do {
    clrscr();
    printf("Praca s dvoma tlacovymi frontami \n\n");
    printf("Pridaj do F1................ 1\n");
    printf("Pridaj do F2................ 2\n");
    printf("Vybavenie................... 3\n");
    printf("Vypis....................... 4\n\n");
    printf("Koniec...................... k\n");

    switch (c = getch()) {
      case '1': pridaj(&zac1, &kon1); break;
      case '2': pridaj(&zac2, &kon2); break;
      case '3': {
                  vybavenie(zac1, zac2);
                  zac1 = kon1 = NULL; 
                  zac2 = kon2 = NULL;
                }
                break;
      case '4': vypis(zac1, zac2); break;
      default: break;
    }

  } while (c != 'k');

  return(0);
}